(x+3)/(x^2-x-2)(x^2-2-3)/(3x+9)

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Solution for (x+3)/(x^2-x-2)(x^2-2-3)/(3x+9) equation:


D( x )

x^2-x-2 = 0

3*x+9 = 0

x^2-x-2 = 0

x^2-x-2 = 0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

3*x+9 = 0

3*x+9 = 0

3*x+9 = 0 // - 9

3*x = -9 // : 3

x = -9/3

x = -3

x in (-oo:-3) U (-3:-1) U (-1:2) U (2:+oo)

(((x+3)/(x^2-x-2))*(x^2-3-2))/(3*x+9) = 0

((x+3)*(x^2-5))/((x^2-x-2)*(3*x+9)) = 0

x^2-x-2 = 0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

(x+1)*(x-2) = 0

((x+3)*(x^2-5))/((x+1)*(x-2)*(3*x+9)) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x^2-5 )

1*x^2 = 5 // : 1

x^2 = 5

x^2 = 5 // ^ 1/2

abs(x) = 5^(1/2)

x = 5^(1/2) or x = -5^(1/2)

x in { -3}

x in { 5^(1/2), -5^(1/2) }

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